A cookie jar has 3 chocolate chips, 2 peanut butter, and 5 oatmeal raisin cookies. If Mo chooses a cookie, does not replace it, then chooses another, what is the probability that he chooses a peanut butter then a chocolate chip cookie?

2 peanut butter /10 total cookies x 3 chocolate chip /9 total cookies = 6/90 = 1/15

1/15 chance

Step-by-step explanation:

1:5, 1:3

Step-by-step explanation:

a cookie jar has 10 total cookies

peanut butter: the probability that he chooses a peanut butter is 2:10 or 1:5

now the cookie jar only has 9 because he took one and didn't replace it

chocolate chip cookie: the probability that he chooses a chocolate chip cookie is 3:9 or 1:3

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3