The graph of the function f(x) = (x − 3)(x + 1) is shown. On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1, negative 4), and goes through (3, 0). Which describes all of the values for which the graph is positive and decreasing? all real values of x where x < −1 all real values of x where x < 1 all real values of x where 1 < x < 3 all real values of x where x > 3

Correct option: first one -> all real values of x where x < −1

Step-by-step explanation:

First we need to find the roots of the function f(x):

0 = (x - 3)(x + 1)

(x - 3) = 0 -> x = 3

(x + 1) = 0 -> x = -1

The roots of the function are x = 3 and x = -1.

The vertex is between the roots (x = 1) and has a negative value of y (y = -4), so the concavity of the parabola is upwards.

So the graph is decreasing until it reaches the vertex, then the graph is increasing.

Then, we can affirm that the graph is positive and decreasing for all real values of x where x < -1 (for x > -1 and x < 3 we have negative values)

Correct option: first one

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

its line 2 i just added the rest or else it wouldn't let me answer