The average horse requires 0.0333 Megacalories (Mcal) each day for every kilogram (kg) it weighs. If your horse weights 588 kg, and the food you are buying provides 1070 kcal per pound of food, how many pounds of food do you need each day for your horse

The horse needs 1.8 pounds of food each day

Since the energy requirement is 0.0333 Megacalories (Mcal) each day for every kilogram (kg) it weighs.

For a 588 kg horse, the energy requirement is:

Energy requirement = 0.0333 Mcal/kg * 588 kg = 19.5804 Mcal

Since each pound of food provides 1070 kcal per pound, hence:

Number of food in pounds needed = 19.5804 Mcal/1070 kcal per pound

Number of food in pounds needed = 19.5804 * 10³ kcal/1070 kcal per pound

Number of food in pounds needed = 1.8 pounds

Hence the horse needs 1.8 pounds of food each day

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18.3 pounds

Step-by-step explanation:

We are given;

Weight of horse = 588 kg

Calories required by horse each day per kg = 0.0333 Megacalories = 0.0333 × 1000 KCal = 33.3 kcal/kg

Thus, calories used by the 588kg horse = 33.3 × 588 = 19580.4 kcal

Now, we are told the food provides 1070 kcal for each pound of food.

So, if 1070 kcal produces 1 pound,

Then, 19580.4 kcal will produce;

19580.4/1070 pounds = 18.3 pounds

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step-by-step explanation:

a roof pitch is basically for every inch rise there is 12 inches run.

the height of the roof is also known as the rafter.

formula: rafter^2 = rise^2 + run^2

rafter^2 = 5^2 + 12^2

rafter^2 = 25 + 144

rafter ^2 = 169"^2

the height of the roof from the lowest point to the highest point is 169"^2.

hope this : )

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step-by-step explanation: