FInd the equation of the line with slope -6 which goes through the point (-9,-6).

y=-6x-60

Step-by-step explanation:

You want to find the equation for a line that passes through the point (-9,-6) and has a slope of -6.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -6. So you can right away fill in the equation for a line somewhat to read:

y=-6x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-9,-6). When x of the line is -9, y of the line must be -6.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -6 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-9,-6).

So, why not plug in for x the number -9 and for y the number -6? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-9,-6). y=mx+b or -6=-6 × -9+b, or solving for b: b=-6-(-6)(-9). b=-60.

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

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