What are the factors of 2x^2+3x-54

(2x - 9)(x + 6) .

Step-by-step explanation:

2x^2 + 3x - 54

Use the 'ac' method to do this.

First multiply the first number by the last:

2 * -54 = -108.

Now we want 2 numbers whose product is -108 and whose sum is + 3,

- these are +12 and -9, so we write:

2x^2 + 12x - 9x - 54        Now factor by grouping:

= 2x(x + 6) - 9(x + 6)        x +6 is common, so:

= (2x - 9)(x + 6) .

3x + 4y -25 =0 represents the amount of change sianna should recieve