Given: DM⩭ME, BM⩭CM, D is the midpoint of AB, E is the midpoint of AC.
Prove: ∠DBM⩭∠ECM

Complete Question

In Triangle ABC

Given: DM⩭ME, BM⩭CM, D is the midpoint of AB, E is the midpoint of AC.

Prove: ∠DBM⩭∠ECM

Proved

Step-by-step explanation:

Given: DM⩭ME, BM⩭CM

Consider Triangles DBM and ECM in the diagram

Since DB and MC are the third lengths of the two triangles with two congruent lengths, then

Therefore:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

step-by-step explanation:

use context clues to figure out the meaning of the bolded word:  

the sage gardener knew when she had to water her plants.  

question 8 options:

mint plant

wise

happy

lazy