Please help me The box plots show male and female grades in a mathematics class:

Box plots titled Male versus Female grades in Math with horizontal axis labeled Math Marks ranges from 55 to 100. Males box plot with minimum approximately between 70 and 75 and maximum approximately at 95 has interquartile ranges approximately between 75 and 90 and median approximately at 80. Females box plot with minimum approximately at 75 and maximum approximately at 100 has interquartile ranges approximately between 75 and 85 and median approximately at 80.

Which of the following best describes the information about the interquartile ranges?

The interquartile range for males is larger than the interquartile range for females.
The female interquartile range is not accurate because the first quartile is missing.
The interquartile range for males is skewed right due to a high median.
The interquartile range for females is larger than the interquartile range for males due to a large outlier.

The IQR for the grades of the female students is larger than the IQR for the grades of the male students.

Step-by-step explanation:

Hello!

The IQR is the difference between the third quartile (Q₃) and the first quartile (Q₁), this is a measurement of statistic dispersion. This value shows the variability of the "mid 50%" of the distribution, is barely affected by extreme values (outliers) and it helps you to identify them.

The box plots (see attachment) are horizontal, the first quartile marks the left limit of the box and the third quartile is the right limit of it.

For the males (green)

Q₁ ≅ 89

Q₃ ≅ 98

IQR= Q₃ - Q₁= 98 - 89= 9

For the females

Q₁ ≅ 82

Q₃ ≅ 97

IQR= Q₃ - Q₁= 97 - 82= 15

The IQR for the grades of the female students is larger than the IQR for the grades of the male students.

Note: These values are approximate, but as you can see the "box" for the male students is smaller than the "box" for the females, so values aside, the IQR for the males is smaller than the IQR for the females.

I hope this helps!

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation:

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.