Omar recorded the number of hours he worked each week for a year. Below is a random sample that he took from his data. 13, 17, 9, 21

What is the standard deviation for the data?

Standard deviation: s = StartRoot StartFraction (x 1 minus x overbar) squared + (x 2 minus x overbar) squared + ellipsis + (x n minus x overbar) squared Over n minus 1 EndFraction EndRoot.

A.) 0

B.) 4

C) 2

D.) 26.7

B) 4

Step-by-step explanation:

Using the formula

Standard deviation = √( (Σ ( x - π)²)/n)

To get the standard deviation, first we workout the Mean which is the simple average of the data set

n = 4

(13 + 17 + 9 + 21) / 4 = 60/4 = 15

Mean(x) = 15

Then (x-π)²

13 - 15 = (-2)² = 4

17 - 15 = (2)² = 4

9 - 15 = (-6)² = 36

21 - 15 = (6)² = 36

Σ ( x - π)² = (4 + 4 + 36 + 36) = 80

Standard deviation = √( (Σ ( x - π)²)/n

= √ (80/4)

=√20

= 4.47

= 4

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%