OA ⊥

OC

start overline, O, A, end overline, \perp, start overline, O, C, end overline

\qquad m \angle AOB = 6x - 12^\circm∠AOB=6x−12

∘

m, angle, A, O, B, equals, 6, x, minus, 12, degrees

\qquad m \angle BOC = 3x + 30^\circm∠BOC=3x+30

∘

m, angle, B, O, C, equals, 3, x, plus, 30, degrees

Find m\angle AOBm∠AOBm, angle, A, O, B:

Step-by-step explanation:

We know that angles BOC and AOB are complementary angles, that is, the sum 90°. Additionally, we know that

and , which can be expressed as

Let's solve for

Using this vale, we find the measure of angle AOB

Therefore, the answer is 36°.

its 36 degrees i just did it

Step-by-step explanation:

believe it or not anna is correct good job anna give me a fist bump there u go gal

m=-16

step-by-step explanation: