Two rigid transformations are used to map TriangleABC to TriangleQRS. The first is a translation of vertex B to vertex R. What is the second transformation? a reflection across the line containing AB
a rotation about point B
a reflection across the line containing CB
a rotation about point C

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Find the zero function by factoring (try to show work) h(x)=-x^2-6x-9

What are the solutions of the system? solve by graphing. y = -x^2 -6x - 7 y = 2