What is the 9th term in an arithmetic sequence with the first term equal to 1 and the constant difference equal to 7?

a9 = 57

Step-by-step explanation:

According to the given information

First Term (a1) = 1 and

Constant Difference (d) = 7

Here,

a1 = 1

d = 7

Now,

a9 = a + 8d

= 1 + 8(7)

= 1 + 56

a9 = 57

Thus, the 9th term in an arithmetic sequence is 57

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.

the radius is 2 times the diameter.

step-by-step explanation: