There are 8 distinct points on a plane, where no three are collinear. An insect starts at one of these points, and walks in a straight line to another point, and continues doing this until it reaches all 8 points, creating 7 segments. What is the maximum amount of times the insect crosses its own path? - Will give Brainliest

Total Number of lines will be 28

Step-by-step explanation:

We can use combinations to solve this question.

Let the two Collinear points be denoted by A and B and the other other points be denoted by x1,x2,x3,x4, x5 and x6.

Suppose that only A and B are collinear.

The number of lines determined by any two of x1 to x6  are given by 6C2= 15

The number of lines from A or B and x1---x6 is given by 6C1 * 2C1= 12

The number of lines from A to B is 1.

Total Number of lines = 15+ 12+ 1= 28

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315