Mathematics, 14.06.2020 21:57 lalop3412

Maltie uses the discriminant to determine the number of zeros the quadratic equation 0 : 3x? - 7x + 4 has. Which best describes the discriminant and the number of zeros?
The equation has one zero because the discriminant is 1.
The equation has one zero because the discriminant is a perfect square
The equation has iwo zeros because the discriminant is greater than 0.
The equation has no zeros because the discriminant is not a perfect square.

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Answer from: LouieHBK

The equation has two zeros because the discriminant is greater than zero.

Step-by-step explanation:

This is the equation to solve:

0=3x^2-7x+4

Recall that the discriminant is the formulation of the quantity that appears inside the square root in the quadratic formula that solves the above quadratic equation. In the quadratic formula, you have a rational number plus or minus the square root of the discriminant we are talking about, divided by a factor. Therefore, as long as the discriminant is not zero, you will have two possible solutions to the equation : one with the plus - when you add, and the other one when you subtract (use the minus option).

The discriminant in this case is given by: $(-7)^2-4\,(3)\,(4)\,=\, 49-48=1$

Square root of 1 is 1 , so in one case you add , and the other one when you subtract this value. A total of two zeros for the equation.

Therefore, the most appropriate answer would be:

The equation has two zeros because the discriminant is greater than zero.

Answer from: Quest

No i refuse to tell you the answer but the estimate is 10

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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