The length of a rectangle is 11 feet more than the width. If the perimeter is 62 feet then what is the length of a rectangle in feet? I dont know how I got 110.

The length is 21 ft

Step-by-step explanation:

w = width

l = w+11

The formula for perimeter is

P =2(l+w)

62 = 2 ( w+11+w)

Combine like terms

62 = 2(2w+11)

Divide each side by 2

62/2 = 2/2 (2w+11)

31 = 2w+11

Subtract 11 from each side

31-11 = 2w+11-11

20 = 2w

Divide each side by 2

20/2 = 2w/2

10 =w

Now find the length

l = w+11

l = 10+11

l = 21

The length is 21 ft

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?