If you’re good with permutations in math 30 please help and answer this easy question below real answers only a graduating class has 10 students with 6 boys and 4 girls. the number of ways the students can be arranged in a line if the girls must be together and the boys must be together is

a) 2(6!)(4!)

b) 10!

c) 6!4!

d) 2 (6) (4!)

 a) 2(6!)(4!)

Step-by-step explanation:

The number of ways the boys can be arranged is: 6!

The number of ways the girls can be arranged is: 4!

The number of ways the groups (boys & girls) can be arranged is: 2

Girls could be in the front .. or in the back ... of the line.

Put these together to get: 6! × 4! × 2

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer