The diagram shows a sector of a circle with centre O and radius 6cm. MN is a chord of the circle.
Angle MON is 50°

calculate the area of the shaded segment.
give your answer to 3 significant figures

Step-by-step explanation:

Area of the shaded segment = area of the sector OMN - Area of the triangle OMN

Area of the sector OMN =

r= radius of the sector

= angle substended by the sector

Area of the sector OMN

Area of triangle ABC =

To get the height, we will use SOH CAH TOA trigonometry identity

According to SOH;

sin 25° = opp/6

opp = 6sin25°

opp = 2.54cm

The base of the triangle = 2(2.54) = 5.08cm

Th height can be gotten using the pythagoras theorem. The hypotenuse = 6cm and the opposite = 2.54cm

the adjacent = height = 5.44cm

Area of the triangle OMN

Area of the shaded region = 15.71-13.82

Area of the shaded region = 1.89cm² to 3sf

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: