A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip. What is the probability that both chips are red? IN SIMPLEST FORM

1/9

Step-by-step explanation:

So, we are given the following data or parameters or infomation in the question above;

=>" A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. "

=> "One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip."

Therefore, the total number of chips in the container = 14 + 10 + 12 = 36 chips.

The probability of drawing a red chip in the first draw = 12/36 = 1/3.

The probability of drawing a red chip in the second draw = 1/3 also.

Thus, the probability that both chips are red => 1/3 × 1/3 = 1/9.

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)