A certain spring has a resting length of 0.08 m (8 cm) when it is not stretched. The spring is stretched to a length of 0.10 m (10 cm), 0.02 m beyond its natural length. Holding it in this stretched position requires a force of 20 N. Question: What is the force function for this spring? Hooke's Law says that the force required to maintain the spring in a stretched position is the linear function F(x) = kx. Find the spring constant, k, for the spring described above, and enter that number as your final answer.

The spring constant is  

Step-by-step explanation:

From the question we are told that

     The resting length is

        The extension of spring is  

      The new length of spring is  

       The force is  

The spring constant is

substituting values

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

im alright what do you need

step-by-step explanation: