N a piece of paper draw segment AB and its midpoint D. Then draw the perpendicular bisector of segment AB and name it ine CD
|/n your journal, write a proof that shows that the distance of point C from endpoint A is the same with the distance of
point C from endpoint B, or in other words prove that CA=CB.

By Side-Side-Side (SSS) property, CA = CB

Step-by-step explanation:

Given: /AB/ and bisector /CD/.

Proof: CA = CB

But,

AD = BD (since D is the midpoint of AB)

<CDA = CDB (right angle property)

<CAD = CBA (congruent property of triangles)

Therefore;

Δ ACD = ΔBCD (congruence property)

= (proportion of the sides of two congruent triangles)

Thus, by Side-Side-Side (SSS) property, CA = CB

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i