Abby Kratz, a market specialist at the market research firm of Saez, Sikes, and Spitz, is analyzing household budget data collected by her firm. Abby's dependent variable is monthly household expenditures on groceries (in $'s), and her independent variables are annual household income (in $1,000's) and household neighborhood (0 = suburban, 1 = rural). Regression analysis of the data yielded the following table. Coefficients Standard Error t Statistic p‐value Intercept 39.14942 22.30182 1.755436 0.109712 x 1.792312 0.407507 4.398234 0.001339
Source df SS MS F Se = 29.51443
Regression 1 16850.99 16850.99 19.34446 r2 = 0.682478
Residual 9 7839.915 871.1017
Total 10 24690.91
For a rural household with $90,000 annual income, Abby's model predicts weekly grocery expenditure of:.
a) $150.35
b) $50.35
c) $1,959.29
d) $128.65
e) $1286.50

d) $128.65

Step-by-step explanation:

The table format from the question can be properly expressed as :

                       Coefficients       Standard Error     t Statistic    p  value

Intercept           39.14942          22.30182             1.755436     0.109712

x                         1.792312          0.407507             4.398234    0.001339

Source            df            SS                MS             F             = 29.51443

Regression      1       16850.99      16850.99   19.34446     = 0.682478

Residual          9       7839.915       871.1017

Total               10       24690.91

For a rural household with $90,000 annual income, Abby's model predicts weekly grocery expenditure of:_________.

The estimated regression equation is as follows:

Expenditure (y) = 39.15 + 1.79 x

For a rural household with $90,000 annual income; the independent variables will assume the following values

x = 50

Thus; the estimated groceries expenditure is computed from the above regression equation by replacing the values of the independent variables;

This can be expressed as:

y = 39.15 + 1.79 (50)

y = 39.15 + 89.5

y = $128.65

what statement? is there an image?

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!