Drag the tiles to the correct boxes to complete the pairs. Match each function to its domain and range.
f(x)=51–3
f(x) = 4-4x
fix)= i +1.5
(o)=-103
Domain and Range
Function
domain: {0, 1, 3, 5, 6}
range: {-20, -16, -8,0,4}
domain: {-2,-1,0,3,4}
range: {-13,-8, -3, 12, 17}
+

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

h/o/e/s mad

step-by-step explanation:

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