Find the values of a, b and c in the equation below (x^5yz^4)^3/x^3yz= x^a y^b z^c

a = 12, b = 2, c = 11

Step-by-step explanation:

Using exponent rules we can distribute the exponent of 3 to the xyz.

This results in the numerator now being. This can be simplified to, .

Now divide the numerator by the denominator subtracting the exponents.

Which equals,

So a = 12

b = 2

and

c = 11

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