- 3x + 2(5x-7) 9- 3(2x - 4)

8x - 613 - 2x)

-5+5(x + 4)

4(6n +9) - 10n

14 - 3(4n-1)

-8n-8(-4-2n)

7k - 2(3k + 1) - 9

-6+5(8-k) - 8k

k+1 - 4(2k-9)

-10k - 3+2(5 + 6k)

8 + 9x + 4(11 - 2x)

-4(-2x - 7) + 6x - 7

9-3(-4 + 3x) + 12x

5(2y - 4) + 2(y + 9)

-4(3u - 1) + 7(3-2u)

6(-5u+1) - 3(4u - 12)

3(-u-5)+8(2u+1)

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.

many reason,

step-by-step explanation:

where is the graph? need more info

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.