Solve systems of equations for x + y, please!! 12x - 8y = -12 6x + 4y = -30

x = -3, and y = -3, or the ordered pair is (-3, -3)

Step-by-step explanation

To solve this system, you can use the elimination method:

First, write both equations down.

12x - 8y = -12

6x + 4y = -30

If you multiply the second equation by 2, you can eliminate x. Rewrite the first equation, and multiply the second one by 2:

12x - 8y = -12

12x + 8y = -60

Once added, you get the equation:

24x = -72

x = -3

Now, we just plug -3 into one of the equations and solve for y:

12x - 8y = -12

12(-3) - 8y = -12

-36 - 8y = -12

-8y = 24

y = -3

So, x=-3, and y=-3, or the ordered pair is (-3, -3)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

it has changed from the width and the height.

step-by-step explanation: