A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped into a container of boiling water (100oC). If the temperature of the sphere increases 15o in 9 seconds, find the temperature of the ball after 18 seconds in the boiling water. (Assume the sphere obeys Newton's Law of Cooling.)

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

We'll solve for k

Divide both sides by -5

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5.5

step-by-step explanation: