The value of y varies inversely as the cube of x and y=1 when x=6. Find the value of y when x =2.

y=27 when x=2

Step-by-step explanation:

y varies inversely as the cube of x

y=k(1/X^3)

y=1 when x=6

y=k(1/X^3)

1=k(1/6^3)

1=k(1/216)

k=1÷1/216

K=1×216/1

k=216

find y when x=2

y=k(1/X^3)

y=216(1/2^3)

y=216(1/8)

y=216/8

y=27

i will pick c put check it over to be sure

step-by-step explanation: