A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation of $0.24. It was felt that breakfasts on the East Coast were higher than $9.33. A sample of 81 business managers on the East Coast had an average breakfast cost of $9.41. At α=0.05, what is the test value?

 (1)  

Replacing the info given we got:

Step-by-step explanation:

Information given

represent the sample mean

represent the sample standard deviation

sample size  

represent the value to verify

represent the significance level

t would represent the statistic

represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:  

Null hypothesis:  

Alternative hypothesis:  

The statistic is given by:

 (1)  

Replacing the info given we got:

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.