For a given rectangle the length equal 3x + 2 and the width equal 5 what is the area of the rectangle

15x + 10.

Step-by-step explanation:

To find the area of a rectangle, recall the formula is A = l × w. Therefore:

A = (3x + 2) (5)

Distribute the '5':

A = 15x + 10

Therefore, the area of the rectangle of 15x + 10.

15x+10 units ^2

Step-by-step explanation:

The area of a rectangle can be found using:

A = l * w

The length of the rectangle is 3x+2 and the width is 5.

l=3x+2

w=5

Substitute these values into the formula.

A= 3x+2 *5

This can be rewritten as: (Commutative property of Multiplication)

A= 5* 3x+2

A= 5(3x+2)

Distribute the 5. Multiply each term inside the parentheses by the number outside the parentheses.

A= (5*3x) + (5*2)

A= 15x +10

A= 15x+10 units^2

The area of the rectangle is 15x+10 square units.

square root

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.