Find the solutions of each equation on the interval [0, 2π). si (3pi/2+x)+ sin (3pi/2+x)=-2 please show work I am stuck

The solutions are 0° and 3π

Step-by-step explanation:

On solving the equation given;

Since sin is negative in the 3rd and 4th quadrant,

In the 3rd quadrant;

x =180°+2π

x = π + 2π

x = 3π

In the 4th quadrant;

x = 360°-2π

x = 2π-2π

x = 0°

i think it's b

step-by-step explanation:

because the graph is 2 above (0,0)

i would say true? if the unit was informational and it "refreshed your understanding", then true.