Edmond doubled the width of the crate. How do the perimeter and the area of the floor of the new crate compare to those of the original crate? Original:length = 1.2 metres width = 0.8 metres

The area would be doubled also

The perimeter will be increased in a factor of 1.4

Step-by-step explanation:

Originally the area of new crate = L * B = 1.2 * 0.8 = 0.96 m^2

perimeter is 2(L+ B) = 2(1.2 + 0.8) = 4 m

Now let’s double the width , it becomes 0.8 * 2 = 1.6 m

Area would be 1.6 * 1.2 = 1.92 m^2 which is two times the previous area

The increased perimeter will be 2(1.6 + 1.2) = 5.6 m

This is an increase in factor of 1.4

30

step-by-step explanation:

times by times

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.