An army surplus store plans on making a tent with the dimensions shown. How much material is needed to make this tent? 15,200 square inches

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10,400 square inches

13,400 square inches

14,500 square inches

15,200in²

Step-by-step explanation:

The tent is shown in the attachment below.

Given=>

Triangular prism tent with the following dimensions:

base (h) = 60in

height of the triangle (h) = 40in

Length of the 3 sides of the triangle respectively (s1, s2, and s3) = 60in, 50in, 50in

Height of the prism (H) = 80in

==>REQUIRED:

Amount of material needed to make the tent = surface area of the triangular prism = bh + (s1 + s2 + s3)*H

==>SOLUTION:

Let us plug in our values using the formula for SA of a triangular prism.

Thus,

SA = 60*40 + (60 + 50 + 50)*80

SA = 2400 + (160)*80

SA = 2400 + 12,800

SA = 15,200in²

Material needed for the tent = 15,200 in²

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

3+x

step-by-step explanation: