Mitch is buying candy bars for his friends. He wants to give 2 bars to each friend, and he wants to have 10 spare bars. He can afford to buy 28 candy bars. What is the algebraic sentence that will help him figure out how many friends he can treat? Let f= the number of friends, and the options I have are (A) 2f+10=28 (B) 2f-10=28 (C) 1/2f+10=28 (D) 1/2f-10=28

A. 2f + 10 = 28

Step-by-step explanation:

28 candy bars.

He wants 10.

28 - 10.

18 candy bars.

He gives each friend 2.

18 divided by 2.

9.

He can treat 9 friends.

Step 1: Subtract 10 from both sides.

2f+10=28

which would take away the 10 and subtract 10 from 28. (That would be Jack's bars.)

2f = 28.

Step 2: Divide by 2 on both sides.

2f = 28

which would cancel out the 2f. And Whatever is done to the left is done to the right, meaning you would divide 28 by 2 aswell. (Dividing up the candy bars among his friends).

f = 9

(c, 0) i might be wrong so don't put full faith on my answer

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation: