I am confused on how to solve this question

Option (1)

Step-by-step explanation:

Quadratic equation is given as,

2x² + 8 = 0

Let the function is,

f(x) = 2x² + 8

f(x) = 2(x - 0)² + 8

Now we will prepare the table for every input value,

x    -2      -1         0        1          2

y     16      10       8        10        16

By plotting these points we get a parabola having vertex at (0, 8).

Graph of the given function doesn't touches or intersects the x-axis.

And we know if a graph has no x-intercept, function graphed will have no real solution.

Therefore, function f(x) will have no real solutions.

Option (1) will be the answer.

cheater

step-by-step explanation:

0.32

step-by-step explanation:

2.24/7