Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation to enable the elimination of the y-term. Add the equations to eliminate the y-terms. Solve the new equation for the x-value. Substitute the x-value back into either original equation to find the y-value. Check the solution. The solution to the system of equations is ( ,

x=0.5 and y=5

Step-by-step explanation:

8x+7y=39...eqn(1)×-14

4x-14y=-68...eqn(2)×7

we now have,

-112x-98y=-546

-(28x-98y=-476)

-140x÷-140 =-70÷-140

x=0.5

to solve for y, we substitute (x=0.5) into eqn (1) or eqn 2 which ever you want...

so I'm using eqn 1.

8x+7y=39

8(0.5)+7y=39

7y=39-4

7y÷7=35÷7

y=5

therefore, x=0.5, y=5

proof: substitute both x and y values to get you the same answer as the original solutions in both equations.

we have,

8(0.5)+7(5)=39

4(0.5)-14(5)=-68

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^