A rancher has 240 feet of fence with which to enclose three sides of a rectangular plot (the fourth side is a river and will not require fencing). Find the dimensions of the plot with the largest possible area. (For the purpose of this problem, the width will be the smaller dimension (needing two sides); the length with be the longer dimension (needing one side).)

Length =120 ft

Width = 60 ft

Area = 60 x 120 = 7,200ft2

Step-by-step explanation:

Hi, to answer this question we have to apply the next formulas:

Replacing with the value given:

240 = 2w+l

Solving for l (length)

l = 240-2w

Substituting l=240-2w

A = w (240-2w)

A = 240w -2w^2

Taking the first derivative of A to find the largest area:

A' = 240-4w

When a =0 , and solving for w

0=240-4w

4w=240

w = 240/4

w = 60 ft

Replacing w in the other dimension:

l = 240-2(60)

l= 240-120=120 ft

length = 120 ft

Area = 60 x 120 = 7,200 ft2

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.