Mathematics, 19.06.2020 21:57 xxYingxYangxx7311

Which expression is equivalent to StartFraction StartRoot 2 EndRoot Over RootIndex 3 StartRoot 2 EndRoot EndFraction? One-fourth RootIndex 6 StartRoot 2 EndRoot StartRoot 2 EndRoot StartFraction StartRoot 2 EndRoot Over 2 EndFraction Answer is RootIndex 6 StartRoot 2 EndRoot B on edg

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Answer from: devbar3416

The expression equivalent to given expression is $\sqrt[6]{2}$ .

Given expression is, $\frac{\sqrt{2} }{\sqrt[3]{2} }$

Expression can be written as,

$\frac{\sqrt{2} }{\sqrt[3]{2} } =\frac{2^{1/2} }{2^{1/3} } =2^{\frac{1}{2}-\frac{1}{3} } \\
\\
2^{\frac{1}{2}-\frac{1}{3} } =2^{\frac{1}{6} }=\sqrt[6]{2}$

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Answer from: taee67

Question:

Which expression is equivalent to

$\frac{\sqrt{2}}{\sqrt[3]{2}}$

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}$

Step-by-step explanation:

Given

$\frac{\sqrt{2}}{\sqrt[3]{2}}$

Required

Simplify

From laws of indices;

$\sqrt[n]{x} =x^{\frac{1}{n}}$

So, the expression can be rewritten as

$\frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{{2^{\frac{1}{2}}}}{2^{\frac{1}{3}}}$

Also, from laws of indices

$\frac{x^a}{x^b} = x^{a-b}$

So, the expression is further solved to:

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{2} - \frac{1}{3}$

Solve exponents as fraction

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{3-2}{6}}$

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}}$

This can be rewritten as

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}$

Answer from: Quest

the central idea is that:

individuals should refuse to cooperate with institutions they believe unjust.

thoreau felt that governments were more often agents of corruption than justice, even democracies, and that just because the majority feels a certain way does not make it just or correct in absolute terms. he uses the fact that slavery exists in our democracy to support this idea.

he goes on to say that, as a result, people should live true to their own internal laws regarding right and wrong, as a product of reflection and a moral life, rather than following every law that society imposes.

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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