Mathematics, 18.06.2020 22:57 dbanks701
Solve for b in the formula 3a+2b =c A.) b=c-3a/2 B.) b= c-2/3a C.) B= 2c/3a D.) b= c-3a
Answers: 3
Mathematics, 20.06.2019 18:02
Acompany did a quality check on all the packs of nuts it manufactured. each pack of nuts is targeted to weigh 18.25 oz. a pack must weigh within 0.36 oz of the target weight to be accepted. what is the range of rejected masses, x, for the manufactured nuts? x < 17.89 or x > 18.61 because |x − 18.25| > 0.36 x < 17.89 or x > 18.61 because |x − 0.36| + 18.25 > 0 x < 18.25 or x > 18.61 because |x − 18.25| > 0.36 x < 18.25 or x > 18.61 because |x − 0.36| + 18.25 > 0
Answers: 2
Mathematics, 21.06.2019 18:50
Astudent draws two parabolas on graph paper. both parabolas cross the x-axis at (-4, 0) and (6,0). the y-intercept of thefirst parabola is (0, –12). the y-intercept of the second parabola is (0-24). what is the positive difference between the avalues for the two functions that describe the parabolas? write your answer as a decimal rounded to the nearest tenth.
Answers: 2
Solve for b in the formula 3a+2b =c A.) b=c-3a/2 B.) b= c-2/3a C.) B= 2c/3a D.) b= c-3a...
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