The length of TR is 17 units. What are the lengths of SV and QT? (please hurry i dont get this question) also i need each individual answer, not SV + QT, I need SV and QT

Step-by-step explanation:

From the diagram, it can be seen that TR is parallel to RV. This means that TR = RV. Given TR = 17 and RV = 3x+2

3x+2 = 17

3x = 17-2

3x = 15

x = 5

RV = 3(5)+2 = 17

QV = 4x+1 = 4(5)+1

QV = 21

Using Pythagoras theorem on ΔQRV to get RQ

QV² = QR²+RV²

21² = QR²+17²

QR² = 21²-17²

QR = 12.33

Using Pythagoras theorem on ΔQRT to get QT

From ΔQRT,

QT² = QR²+TR²

QT² = 12.33²+17²

QR² = 152.0289+289

QT² = 441.0289

QT =21

Since TS = 9(5)-4 = 41

Using Pythagoras theorem on ΔTRS

From ΔTRS,

TS² = RS²+TR²

41² = RS²+17²

RS² = 41²-17²

RS² = 1392

RS = 37.31

Similarly Using Pythagoras theorem on ΔRSV

From ΔRSV,

SV² = RV²+RS²

SV² = 17²+37.31²

SV² = 1681.0361

SV = 41

answerthe vertex form

step-by-step explanation: