Find the coordinates of H' after a reflection across the parallel lines; first across y = -2 and then across y = 2. Answer in form (a, b). Part 7a

H' = (-4, 4)

Step-by-step explanation:

H = (-4, -4)

reflect across y = -2:

H is 2 units below y = -2 so when reflected it will be 2 units above y = -2

--> the x-coordinate doesn't change    the new y-coordinate is: 0

H' = (-4, 0)

reflect across y = 2:

H' is 2 units below y = 2 so when reflected it will be 2 units above y = 2

--> the x-coordinate doesn't change    the new y-coordinate is: 4

H'' = (-4, 4)