What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
point (-4, 3)?
y-3 = -2(x + 4)
Y-3 = -
2(x+4)
y-3 = {(x + 4)
Y-3 = 2(x + 4)

y=1/2x+5

Step-by-step explanation:

the perpendicular line equation's slope is a negative reciprocal, so the new equation's slope is 1/2. so now you have y=1/2x+b plug in (-4,3) to find b. so you will do 3=1/2(-4)+b. 3=-2+b and then you solve for b. you would get b=5. so, the new equation is y=1/2x+5

y=mx+b

step-by-step explanation:

m slope, b y-intercept

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)