In circle M, diameters JL and HK each measure 16 centimeters.
What is the approximate length of minor arc JH? Round to
the nearest tenth of a centimeter.
3.5 cm
K
25
6.9 cm
21.6 cm
46.8 cm
M
J
H
Next
Mark this and return
Save and Exit
Submit

3.5 cm

Step-by-step explanation:

In the picture attached, circle M is shown.

From the picture, minor arc JH measures 25°.

The length of the circle is π*Diameter = π*16 = 50.26 cm. This length is proportional to 360°. To find the length of minor arc JH, we have to use the next proportion:

50.26 cm / x cm = 360° / 25°

x = 50.26*25/360

x = 3.5 cm

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.