How does the domain change when finding the extremum of a function with and without constraints

if we want to find the maximum or minimum of a function, there are some methods, like see where the derivate is equal to zero and such.

Now, if we have a constraint, for example x> 4

This obviously changes the domain of the possible points where we can find the extremum.

But particularly, we can check at x  = 4 and see it there is a maximum.

if the constraint is x > 4, then then we may found a upper/lower bound.

if the constraint is x ≥ 4, then we may find a maximum/minimum.

Now, when we work with more complex situations, like find the maximum value of f(x) while we have the constraint g(x) = x^4 + x^3 + x^2 = 5

Then the domain will be equal to the intersection of the domains of both functions:

This means, the only possible values that we can input in f(x) to search the extremes, are the values of x such that x^4 + x^3 + x^2 = 5, so this relation defines our new domain (remember that f(x) also may have problems in some values of x, this is why we take the intersection of the domains of f(x) and g(x))

This means that constraints can limit a lot the domain of our functions.

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

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step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b