The mean final exam score of 35 students who had calculus in high school is 77.3 (with a standard deviation of 6.8); while the mean exam score of 23 students who had not had calculus in high school is 73.6 (with a standard deviation of 7.4). What is the standard error for a confidence interval comparing these two means? Question 3 options:

333333333333333333333333333333

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

13.46

step-by-step explanation:

16.80 x .20 = 13.46