Question 2. A square is drawn on the altitude of an equilateral triangle of side 2m (0) What is the area of the square? (ii) What is the altitude of the triangle? iii) What are the lengths of the other two sides of the triangle shown below?

step-by-step explanation:

do you have a copy of the table?

it is probably the graph on the bottom right.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)