The complex solution to a quadratic equation is below. Write this solution in standard form, a+bi, where a and b are real numbers. What are the values of a and b.

a = -6 and b = 3√2

Step-by-step explanation:

Given the complex solution below;

x = (-24±√-288)/4

Re writing in the standard format a,+bi

x =( -24±√144×√2×√-1)/4

In complex notation, i = √-1

x = (-24±√144×√2×i)/4

x = ( -24±12×√2i)/4

x = -24/4±12√2i/4

x = -6±3√2i

Comparing the resulting complex number with a+bi

a = -6 and b = 3√2

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

the answer is simply just 6n add the two together as they have an n