In right triangle ABC on hypotenuse AB lies points K and M such that AK=AC, BM=BC. Find m∠MCK.

The measure of ∠MCK is 45°

Step-by-step explanation:

The parameters given are;

ΔABC with hypotenuse side AB

Let AB = x

BC = y

AC = z

∴ x² = y² +  z²

∠BCM = ∠CMB  (Base angles of isosceles triangle ΔBMC)

Similarly, ∠ACK = ∠AKC (Base angles of isosceles triangle ΔKAC)

∴ ∠BCM + ∠CMB + ∠CBM = 180° (Sum of interior angles in a triangle)

Hence, 2 × ∠BCM + ∠CBM = 180°(1)

Similarly, 2 × ∠ACK + ∠CAK = 180°(2)

Hence, 2 × ∠BCM + ∠CBM = 2 × ∠ACK + ∠CAK

However, ∠CBM + ∠CAK + 90° = 180° (Sum of angles in right triangle ΔABC)

∴∠CBM + ∠CAK = 180° - 90° = 90°

Adding equations (1) and (2), we have;

2 × ∠BCM + ∠CBM + 2 × ∠ACK + ∠CAK = 180° + 180° = 360°

Which gives;

2 × ∠BCM + 2 × ∠ACK + ∠CBM + ∠CAK = 360°

Where;

∠CBM + ∠CAK = 90°, we have;

2 × ∠BCM + 2 × ∠ACK + 90° = 360°

∴ 2 × ∠BCM + 2 × ∠ACK = 360° - 90° = 270°

∠BCM + ∠ACK = 270°/2 = 135°

∠BCM = ∠CMB

∴ ∠CMB + ∠ACK = 135°

Also, ∠CMB = ∠CMK and ∠ACK = ∠MCK

Hence, ∠CMK + ∠MCK  = 135°

However, ∠CMK + ∠MCK + ∠MCK = 180° (Sum of interior angles in a triangle)

Which gives;

∠CMK + ∠MCK + ∠MCK = 135° + ∠MCK = 180°

∴ m∠MCK = 180° - 135° = 45°.

The measure of ∠MCK, m∠MCK = 45°.

10 you would take 50/ .2

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05