The function s(t) represents the position of an object at time t moving along a line. Suppose s (1 )equals 62 and s (5 )equals 102. Find the average velocity of the object over the interval of time [1 comma 5 ].

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time

Step-by-step explanation:

Given;

function s(t) represents the position of an object at time t moving along a line.

s(1) = 62 at t1 = 1

s(5) = 102 at t5 = 5

Velocity v = distance/time

Average velocity v over time t is;

v = ∆s/∆t

v = [s(5) - s(1)]/[t5 - t1]

Substituting the given values;

v = (102 - 62)/(5 - 1)

v = 10

the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.