Really need help it’s due tomorrow

C) 38

Step-by-step explanation:

You are solving for m∠QSR.

Given:

m∠TSR (Total of the two angles) =  70

m∠QST = 2x

m∠QSR = 3x - 10

Set the two angles equal to the total measurement of angles:

2x + 3x - 10 = 70

Simplify. Combine like terms. Add 2x & 3x:

2x + 3x = 5x

5x - 10 = 70

Next, isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 10 to both sides:

5x - 10 = 70

5x - 10 (+10) = 70 (+10)

5x = 70 + 10

5x = 80

Next, divide 5 from both sides:

(5x)/5 = (80)/5

x = 80/5

x = 16

Then, plug in 16 for x in the expression given. Remember you are solving for m∠QSR.

m∠QSR = 3x - 10

m∠QSR = 3(16) - 10

m∠QSR = 48 - 10

m∠QSR = 38

C) 38 is your answer.

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38

Step-by-step explanation:

the sum of two angles =70

2x+3x-10= 70

5x=80

x=80/5=16

QSR= 3x-10=3*16 -10= 48-10= 38

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.