If p(y) = y^3+3 y^2-5y-6, then p (-3) =

9

Step-by-step explanation:

Hope this helps!

p(-3)=9

Step-by-step explanation:

This question ask us to find p(-3), or what p(y) is when y is equal to -3.

We know that:

p(y)= y^3+3 y^2-5y-6

We want to find p(-3), so substitute -3 in for every y.

p(-3)= (-3^3)+3(-3^2)-5(-3)-6

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponents first (-3^3 and -3^2)

-3^3=-3*-3*-3= -27

-3^2= -3* -3= 9

p(-3)= -27+ 3(9) -5(-3) -6

Next, multiply 3 and 9

p(-3)= -27+27-5(-3)-6

Then, multiply -5 and -3

p(-3)= -27+27+15-6

-27 and 27 equal 0, so they cancel each other out.

p(-3)=15-6

p(-3)= 9

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

step-by-step explanation:

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