I will make you as brainliest Suggest a committee that needs 5 members to plan a fundraiser. The candidates consist of 24 girls and 16 boys. What is the probability that at most 2 girls will be on the committee?

30.77%.

Step-by-step explanation:

There are a total of 40 members.

24 girls 16 boys.

Prob( 0 girls being chosen - so all boys ) =  16/40 * 15/39*14/38*  13/37*12/36 = 0.0063956

Prob( first one to be chosen is a girl  then all boys) = (24/40*16/39*15/38*14/37*13/36) = 0.013276

There are 5 ways of 1 girl being chosen so

Prob(1 girl out of 5 chosen) = 0.013276 * 5 = 0.06638

Prob( First 2  chosen are girls then all boys) = 24/40 * 23/39 * 16/38*15/37*14/36

= 0.023489

Number of ways of 2 girls being chosen is 5C2 and so the probability of 2 girls

= 0.023489 * 5C2

= 0.023489 * 10

= 0.23489.

Required probability = 0.23489 + 0.06638 + 0.0063956.

= 0.3076656

= 30.77% to the nearest hundredth.